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my kitten has had the squits since i got him, hes been to the vets and has been starved and put on dietry food, hes had his first lot of jabs (he cant have his 2nd lot till hes better) and has been wormed, ive given the vet a poo sample, wot will they be checking for...?.

Richard W. Bulliet a professor of history at Columbia University, who specializes in the history of Islamic society and institutions, highlights this point in The Case for Islamo-Christian Civilization, ??minutely studying case after case, they have shown that justice was generally meted out impartially, irrespective of religion, official status, gender?not being subject to the sharia, Jews and Christians were free to go to their own religious authorities for adjudication of disputes

Hope you can help me.. Thank you.. it's like joining puzzle pieces to form the whole image..

a) Mississippi is an 11-letter word, so any 11-letter word formed from it is simply a permutation of the letters. There are 11! such permutations, but not all of them are distinct, because some of the letters are identical. The number of times each distinct word will be repeated in a list that assumes that the Ss, Ps, and Is are all distinct is simply the number of ways the Ss can be permuted amongst themselves times the number of ways the Ps can be permuted amongst themselves times the number of ways the Is can be permuted amongst themselves, which is 4!*2!*4!. Therefore, the total number of distinct permutations is 11!/(4!*2!*4!), which is 34650.. . a-i) There are 2*10! permutations starting with P, and each distinct word in the list will again be counted 4!*2!*4! times, so the total number of distinct permutations starting with P is 2*10!/(4!*2!*4!), which is 6300.. . a-ii) In this case, we can consider the block SSSS to be a single symbol, in which case MISSISSIPPI contains eight symbols - one SSSS, 4 Is, 2Ps, and one M. Therefore, the total number of distinct permutations is 8!/(4!*2!), which is 840.. . b) There is a bijection between the 10-letter words that can be formed and the 11-letter words, given by appending the one remaining letter to the end of the 10-letter word. Therefore, the total number of 10-letter words is simply 34650.. . b-i) Considering the IIII as a single symbol, and using the reasoning in a-ii, there are 840 11-letter words formed having all four Is together. However, not all of them can be truncated to form valid 10-letter words, since if IIII is the last symbol, removing it creates a 7-letter word. We must therefore remove those 11-letter words containing the block IIII as the last symbol. There is one of these for each way of permuting the remaining 7 characters, of which there are 7!/(4!*2!) or 105. Therefore, the number of valid 10-letter words is 840-105 or 735.

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